| Username |
Post |
| kale_keta |
Posted
on 11-May-04 09:37 AM
(1)
The sum of three numbers is -11. The first, minus the second, plus 4 times the tird, is -7. The third, plus 3 times the first, plus the second, is -19. What are the numbers ?
(2)
Then nepal Rastya Bank contains only nickels, dimes, and quarters. There are 58 coins in all, valued at $4.95. The number of nickels is 10 short of being three times the sum of the number of dimes and quarters together. How many dimes are in the bank ?
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| kale_keta |
Posted
on 11-May-04 09:38 AM
who gonna b smart in this sajha....................ans those question.............
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| KaLaNkIsThAn |
Posted
on 11-May-04 09:50 AM
duhhh!! urghhh-ummmmm... phew!!!
I quit...
I haaping...
Ask some dumb questions insted... with the title "who is dumb?"... I might answer that! :)
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| nsshrestha |
Posted
on 11-May-04 09:54 AM
Not trying to be smart, I just enjoy this.
1.
x + y + z = -11
x - y + 4*z = -7
z + 3*x + y = -19
2.
x + y + z = 58
5 * x + 10 * y + 25 * z = 495
x - 10 = 3(y + z)
Now can you solve the equations?
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| niksnpl |
Posted
on 11-May-04 10:13 AM
The answers for the 1st prblem:
x= - 4
y= - 5
z= - 2
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| kale_keta |
Posted
on 11-May-04 10:16 AM
niksnpl u got right ans..but wat is the asn of 2nd ques...
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| kale_keta |
Posted
on 11-May-04 10:17 AM
thanks nssshrestha ..
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| cool_keta |
Posted
on 11-May-04 10:18 AM
kale_keta imitated my name !!!!!
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| kale_keta |
Posted
on 11-May-04 10:19 AM
another ques...
find the dimensions of a rectangular enclosure with perimeter 34 ft and area 60 ft squre...
write down ans
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| niksnpl |
Posted
on 11-May-04 10:24 AM
For the second problem!!
The third Equation is incorrect:::
The correct one is x + 10 = 3 ( y +z )
or x = 3 ( y + z ) - 10 [ For clarity ]
It gives the soln:
x = 41
y = 9
z = 8
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| niksnpl |
Posted
on 11-May-04 10:28 AM
The eqns are:
let x be lenght
y be breadth
the perimeter = 2 ( x + y ) = 34
area = x.y = 60
Try to solve...
if n't post it!! i will help you..
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| kale_keta |
Posted
on 11-May-04 10:35 AM
still got pro.........
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| kale_keta |
Posted
on 11-May-04 10:40 AM
wat is the ans of 2nd ques..and 3rd
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| nsshrestha |
Posted
on 11-May-04 10:41 AM
niksnpl, u r rite
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| niksnpl |
Posted
on 11-May-04 12:51 PM
Hey Kale Keta !! Don't be so lazy............:P:P:P
Try to do something..........
I will give you some hints for the 3rd one.........
the perimeter = 2 ( x + y ) = 34
=> x + y = 17 -------------------------( I )
area = x.y = 60
=> y = 60/x -------------------------(II)
Put the value of y from ( II ) to ( I ):
Then you will get the value of x from ( I )
The eqn will be quadratic equation giving two values of x. neglect the negative value as the lenth of rectangle must be greater than zero...
when you get x, you can get y easily...............
Have fun!!!!!!!!!!
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| MillionDollars |
Posted
on 11-May-04 12:53 PM
Bloody nerds here... Let me get out of here...
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| Nepali_boy |
Posted
on 11-May-04 01:17 PM
hy try to do byurself
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| provein |
Posted
on 11-May-04 01:42 PM
perimeter = 34 ft
area = 60 sq. ft
2(x+y) = 34
x*y =60 -> y=60/x
2x +2y = 34
2x + 120/x = 34
(2x^2 +120)/x = 34
2x^2 - 34x + 120 = 0
2x^2 - 10x - 24x + 120 = 0
2x(x-5) - 24(x-5) = 0
(2x-24)(x-5) = 0
2(x-12)(x-5) = 0
(x-12)(x-5) = 0
x = 12 or 5
If x =12, y = 5, If x = 5, y = 12
2*5 + 2*12 = 10 + 24 = 34ft
5*12 = 60 sq ft.
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| provein |
Posted
on 11-May-04 01:46 PM
that was a traditional mathematical process
shortcut is to just divide 34 by 2 (because it is twice x+y), which gives you 17.
then just choose a combination which adds up to 17 and has a product of 60
in this case it won't take you more than 1 minute to see that its obviously 12 and 5.
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| niksnpl |
Posted
on 11-May-04 02:12 PM
OK guys and girls ( though girls have mathphobia :P:P) one more problem:::
( a + b + c ) ^ 2 = a^2 + b^2 + c^2 + 2 ( ab + bc + ca)
( a + b + c ) ^ 3 = ?????
Cheers:::::::::::::::: :U
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| Poonte |
Posted
on 11-May-04 02:16 PM
Aafulai ta hisaab bhanyo ki pisaab aunchha...
Tatto na chharro aruko math HW garera basnu bhanda gayen ma ta jhaadi tira mutna...oye, kanchha! Koi aayo bhane siti baja hai!
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| niksnpl |
Posted
on 11-May-04 02:24 PM
LA POONTe Dai!!
aafno bigat lai thesari birsana ta bhayana ni..POONTE dai!!!
birsini bho, thyo school din haru..........jaabo thehi hisaab garna na-aayera,, pisaab matra aayera....tauka kanyauda kanyaudai.....school sakida samma ta......Hamro PYaro Poonte DAi PURA TAALU>........tauko ma AALO PHalne gari..........Thyo aalo pani kaha falya khaha chha.???.....PARIKSHYA ko NATIJA MA...HEHEH ani POONTE ko Buba le Saikal bata bora ka bora AALO osareko katha azhai purano bhayako chhaina...KI kaso poonte dai????
Cheers::
Mathematics is the Queen of Sciences:
Number Theroy is the Queen of Mathematics..........
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| Poonte |
Posted
on 11-May-04 02:29 PM
aaloo ta hoina...baru mero chillo khapparaan kauli falyo bhane chai ali ramrai dekhinthyo ki? ;)
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| niksnpl |
Posted
on 11-May-04 02:34 PM
POONTE dai!!
FERI ek chhoti hisaab padhna suru garou...... Tapai ko chillo tauko ma KAAULI matra hoina, TAMATAR, BANDA, PARBAL, MULA, GAAJAR sabai falna suru garchha........
Aba Poonte dai, Suru garne hoina ta Hisaab padhna suru!! Pisaab gari gari bhaya pani Hisaab padhou HAi!!!! :P:P:P
;))
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| scatterbrain |
Posted
on 11-May-04 02:42 PM
One of the possibilities:
(a + b + c)^3 = a^3 + b^3 + c^3 + ab(a + b) + bc(b + c) + ca(c + a) + 2(a + b + c)(ab + bc + ca)
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| Poonte |
Posted
on 11-May-04 02:43 PM
Luki luki pisaab garda jarsaab ko memsaab le dekhera laaja marnu bhai raa bela feri hisaab ko kura garchha yo niksnpl karsaab ko naati pani...dhet!
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| niksnpl |
Posted
on 11-May-04 02:53 PM
Nice try Scatter Brain!!!
Could you make it little nicer????? Still some work to do!!! :U:U
First three are perfect, heheeh
ani Poonte Dai lai feri yauta suzhab bhannu ki sallah::
Hisaab Garda Pisaab Aayo Bhanera, jarsaab ko memsaab ko agadi nai jaanu parne ke jarurat thiyo.... Galti garne aafu, Dosh chahi hisaab lai......ya ta bhayena hai!!!
Aafu Thau ma Pisaab garna najanne, Hisaab lai dosh!!!
hahahahah;;;;;;;;;;;;;;;;;;))))))))))))))))))
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| scatterbrain |
Posted
on 11-May-04 03:05 PM
Something like...
(a + b + c)^3 = a^3 + b^3 + c^3 + 3{ab(a + b) + bc(b + c) + ca(c + a) + 2abc} ?
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| niksnpl |
Posted
on 11-May-04 03:11 PM
It's fine,
but I didn't like that term 2abc and some more simplification........When you will find that ............ you will say yourself, WHAT A BEAUTY????!!!
It has Close relation with the expansion of ( a + b + c ) ^ 2, that's why it was there earlier...
Best of Luck .........YOu are very close;;;;;;;;;;;;;;)))
Cheers!!!
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| scatterbrain |
Posted
on 11-May-04 03:11 PM
Here's one for you niks et. al.:
Eric has four children: Albert, Brad, Carla, and Daisy (in order from oldest to youngest). Brad is 4 years older than Carla and 12 years older than Daisy. This year Eric notices that he is twice as old as Brad, and the sum of the squares of the children's ages equals the square of Eric's age. If Daisy just became a math teacher, what is the sum of the children's ages?
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| niksnpl |
Posted
on 11-May-04 04:45 PM
According to you:
E, A, B, C , D be ages.
1) B = C + 4
2) B = D + 12 From 1) and 2), C = D +8
3) E = 2B
A^2 + B^2 + C^2 + D^2 = E^2
Subsituting the values of B, C, and E in the above Eqn, we get
A^2 = D^2 + 56 D + 368
According to Question , D just became Math Teacher :
So, for the D belongs to N, => A also belongs to N. where, N= natural number.
for D = 26 ( which is the minimum value that gives natural A ), A =50
Therefore,
B = 38, C= 34 and E = 76
And Finally Answer to your Question:
The sum of Ages of the childres:
now simple now, isn't it????
A + B + C + D = 148
Cheers!!!!!!!!
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| An Indun Poet |
Posted
on 11-May-04 04:55 PM
Three mathematicians are applying for a job. There are 5 hats,
3 white, 2 black. They're lined up, and a hat is placed on each.
The first person in line cannot see any hat; the second in line
sees only the hat of the person in front of him; the third person
sees only the hats of the two people in front of her. The first
person to correctly figure out what color hat they have gets the
job; you guess wrong and you are killed. Assume these are INTELLIGENT
mathematicians, and that they will do the logically correct thing
at each stage -- if something can be deduced, they will. After a
long pause, the first person, who cannot see any hats, says he knows
the color of his hat. What is the color, and how does he know?
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| scatterbrain |
Posted
on 11-May-04 05:26 PM
Very well done, niks! Impressive.
As for the minimum value of D being 26, I am assuming you are only considering the possible value of D as a math teacher. However, the smallest positive value in N that also produces a value in N for A is 2. I am sure you were aware of that.
------
As for your expansion of (a + b + c)^3, I think I have found what you want.
(a + b + c)^3 = a^3 + b^3 + c^3 + 3(a + b)(b + c)(c + a) ?
Haven't verified it yet; didn't have enough time for that in my class break, but expansion using (a + b)^3 = a^3 + b^3 + 3ab(a + b) seems to point me to that result. :) You be the judge.
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| scatterbrain |
Posted
on 11-May-04 05:44 PM
An Indun Poet : White?
If the first two were wearing black, the third person would have the answer right away.
So at least one of the first two must be wearing a white.
Sensing this delay, the second person would have gotten the answer if the first person was wearing black . But he's quiet.
Aware of the hesitations of the two, the first person knows he's wearing a white hat.
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| An Indun Poet |
Posted
on 11-May-04 06:28 PM
You're Good, Here try another one:
The police rounded up Jim, Bud and Sam yesterday, because
one of them was suspected of having robbed the local bank.
The three suspects made the following statements under
intensive questioning.
Jim: I'm innocent.
Bud: I'm innocent.
Sam: Bud is the guilty one.
If only one of therse statements turns out to be true, who
robbed the bank?
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| scatterbrain |
Posted
on 11-May-04 06:49 PM
Bob? Need to work out the details though, maybe it's him, maybe not. :)
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| scatterbrain |
Posted
on 11-May-04 07:57 PM
On second thoughts, I think it's Jim.
T = True T = False
If Jim T, then Bud isF and Sam is T. Bud is the killer, but this would have two T's.
If Sam is T, then Bud is F and Jim is T. Again two T's.
If Bud is T, then Sam is F and Jim is F. One T in this statement, so the killer is Jim.
Again, I could be way wrong. :)
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| DWI |
Posted
on 11-May-04 08:50 PM
Jim for sure.
Here are the three possibilities:
case I
Jim: I'm innocent.
Bud: I'm not innocent.
Sam: Bud is not the guilty one.
This can't be right, Bud and Sam are in conflict.
case II
Jim: I'm not innocent.
Bud: I'm innocent.
Sam: Bud is not the guilty one.
All three sound right, no conflict observed.
case III
Jim: I'm not innocent.
Bud: I'm not innocent.
Sam: Bud is the guilty one.
Bud and Sam are in agreement, but Jim also is confessing. There is only one suspect, not two
THUS CASE II is true, i.e JIM is the robber.
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